If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1225=5x^2
We move all terms to the left:
1225-(5x^2)=0
a = -5; b = 0; c = +1225;
Δ = b2-4ac
Δ = 02-4·(-5)·1225
Δ = 24500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{24500}=\sqrt{4900*5}=\sqrt{4900}*\sqrt{5}=70\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-70\sqrt{5}}{2*-5}=\frac{0-70\sqrt{5}}{-10} =-\frac{70\sqrt{5}}{-10} =-\frac{7\sqrt{5}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+70\sqrt{5}}{2*-5}=\frac{0+70\sqrt{5}}{-10} =\frac{70\sqrt{5}}{-10} =\frac{7\sqrt{5}}{-1} $
| 2*8-1=x | | 5(8-y)=-(y-4 | | x=5/3x | | y-23=34 | | 3(x+15)=2(3x-1,5) | | 1-4y=-31 | | 16j-12j+3j+2=9 | | 4.2x+8(19.4)=41.8 | | 4x+5x=7x+22 | | 3x-5(x-5)=-8+5x-9 | | 2x+5(3x+7)=16 | | 4-1=14+x | | R+3=r-9 | | 1-4t=-31 | | 2x+20+18x+6+54=180 | | 5g+5g-6g-1=19 | | 4-1=x+14 | | 0.6e=3.4 | | 10+9s=6s-8-9 | | (2x+2)(5x+3)=180 | | 3(x-5)=5-(4x-15) | | 5-4f=5f+10 | | 4(x-5)=7+x | | 10-2u=-2u+10 | | 5x2+14=4 | | 5v-v+3=9 | | m+7=34 | | -9w=7-10w | | 81(7x-3)=8x+6 | | 20y-15y+4y=18 | | 2x+5=x+(-1) | | t-184=36 |